IPL 2019 KXIP vs SRH: Punjab opt to bowl; Hyderabad go unchanged

Both the teams have six points in their receptive kitties and will look forward to altering their standing in the tally

Looking to overcome from their previous loss, Kings XI Punjab is all set to host the Sunrisers Hyderabad at home on Monday night. Both the teams have six points in their receptive kitties and will look forward to altering their standing in the tally. Coming to the toss, home team skipper Ravi Ashwin has won the toss and have opted to bowl first. They have made two changes for the game – Andrew Tye and Murugan Ashwin miss out, Mujeeb-ur-Rahman and Ankit Rajpoot come in. “It is more to do with the venue and the opposition. Mujeeb knows the conditions here and will use Rajpoot to swing the ball early. They (Warner and Bairstow) are quality players. Obviously, a good ball is a good ball, there is a bit in it (surface), just try and swing the ball and probably have them nick off,” said Ashwin at the toss. On the other hand, Bhuvneshwar will once again lead the SRH and they are going unchanged. “We would have bowled first as well. There is no option now. We have to set a total. This is a ground where dew is a big factor. It is one of the areas we would like to improve. But if you look at our games, it was the first game they got a chance. It (bowling) is going good and I am really enjoying it,” said Bhuvneshwar. Here are the playing XIs: Sunrisers Hyderabad: David Warner, Jonny Bairstow(w), Vijay Shankar, Manish Pandey, Deepak Hooda, Yusuf Pathan, Mohammad Nabi, Rashid Khan, Bhuvneshwar Kumar(c), Siddarth Kaul, Sandeep Sharma Kings XI Punjab: Lokesh Rahul(w), Chris Gayle, Mayank Agarwal, Sarfaraz Khan, David Miller, Mandeep Singh, Sam Curran, Ravichandran Ashwin(c), Ankit Rajpoot, Mohammed Shami, Mujeeb Ur Rahman