Star Indian opener Rohit Sharma on Sunday became the batsman with the most number of sixes in the T20I format. The Indian vice-captain in the limited-over format blasted three sixes to go past West Indies's Chris Gayle at the top spot. The right-handed batsman now has 107 sixes in the format whereas Gayle has 105.

The left-handed Gayle is not playing the three-match T20I series as he has been rested by the Windies team management.

Kiwi opening batsman Martin Guptill sits on the third position with 103 sixes.

The 32-year-old Sharma is currently the highest run-scorer in T20Is and he also holds the record for the most number of centuries (four) in the T20I format.

Earlier, India elected to bat first after winning the toss in the second T20 international against the West Indies here on Sunday. Captain Virat Kohli said at the toss that India were fielding the same side which won the first T20 on Saturday by four wickets.

West Indies skipper Carlos Brathwaite said that Sunil Narine will open the batting with John Campbell out of the team.

Teams

India: Rohit Sharma, Shikhar Dhawan, Virat Kohli (captain), Rishabh Pant (wicketkeeper), Manish Pandey, Krunal Pandya, Ravindra Jadeja, Washington Sundar, Bhuvneshwar Kumar, Navdeep Saini, Khaleel Ahmed

West Indies: Evin Lewis, Sunil Narine, Nicholas Pooran (wicketkeeper), Kieron Pollard, Shimron Hetmyer, Rovman Powell, Carlos Brathwaite (captain), Keemo Paul, Khary Pierre, Sheldon Cottrell, Oshane Thomas