The table-toppers, Sunrisers Hyderabad (SRH) are set to lock horns with Rohit Sharma-led Mumbai Indians (MI) on Saturday. The support of the Orange Army will definitely augur well for Hyderabad and the kind of form the openers have shown - Jonny Bairstow and David Warner - means that the Mumbai bowlers will have their task cut out.

But the MI bowling too has shown sparks and Jason Behrendorff showed what he is capable of when he derailed the CSK batting right at the top in the last encounter.

Coming to the toss, SRH have won the toss and elected to bowl first. they have decided to field an unchanged Playing XI for the game.

“We are going to bowl first. Williamson is close to 100% fitness, but we aren't even halfway through the tournament and with the World Cup coming up he doesn't want to take any chance,” said Bhuvneshwar at the toss.

On the other hand, MI have made two changes for the game. Lasith Malinga has flown down to Sri Lanka, hence, Alzarri Joseph replaces him. Also, Yuvraj misses out and Ishan Kishan comes in.

“Just a different strategy and we worked out what these guys like to do here. And it is now important to assess the first two overs and then see what happens after that. I think we have a bowling attack that can defend any total on any track and keeping all of that in mind we are ready and set for this game,” said Rohit Sharma.

Here are the Playing XIs:

SRH: David Warner, Jonny Bairstow(w), Vijay Shankar, Manish Pandey, Deepak Hooda, Yusuf Pathan, Mohammad Nabi, Rashid Khan, Bhuvneshwar Kumar(c), Sandeep Sharma, Siddarth Kaul

MI: Quinton de Kock(w), Rohit Sharma(c), Suryakumar Yadav, Ishan Kishan, Hardik Pandya, Kieron Pollard, Krunal Pandya, Jason Behrendorff, Rahul Chahar, Alzarri Joseph, Jasprit Bumrah