IIT JEE Advance 2019 second topper Himanshu Singh says hard work is important

The results of JEE (Advanced), 2019 were announced on Friday, with Gupta Kartikey Chandresh of Maharashtra emerging as the topper. Of the total number 1,61,319 candidates who appeared in both paper one and two of the exam, 38,705 have cleared the exam.
ABP News talked to all India secodn topper Himanshu Singh. Watch video for more details.