The home team, KXIP, has won the toss and decided to field first. Varun Chakravarthy, who delivered the most expensive first over on his IPL debut, has been replaced by spinner Murugan Ashwin in today's game.
"We will be bowling first. We want to make conditions in the daylight and make use of the easier batting conditions later on when the lights come on. We did win our games last time although it were just three matches, we also won the day game last season," said Ashwin during the toss.
On the other hand, MI have made no changes to the playing XI for this game.
"We would have batted first anyway, so not really fussed. Having said that, we need to play good cricket. We were able to win our last game due to the bowling we had and it's about putting enough runs on the board for them," Said Rohit during the toss.
Here're the Playing XIs:
Mumbai Indians: Quinton de Kock(w), Rohit Sharma(c), Suryakumar Yadav, Yuvraj Singh, Kieron Pollard, Hardik Pandya, Krunal Pandya, Mitchell McClenaghan, Mayank Markande, Jasprit Bumrah, Lasith Malinga
Kings XI Punjab: Lokesh Rahul(w), Chris Gayle, Mayank Agarwal, Sarfaraz Khan, David Miller, Mandeep Singh, Hardus Viljoen, Ravichandran Ashwin(c), Murugan Ashwin, Mohammed Shami, Andrew Tye
Ashwin’s men went through a huge blow against Kolkata Knight Riders in their previous encounter where Andre Russell brutally punished them at the Eden Gardens. A no-ball, due to improper field placement, made them pay a huge price. However, they would look forward to regaining the momentum at home ground.
On the other hand, Mumbai Indians (MI) tasted victory in their previous encounter and will definitely continue the form today as well. Bumrah has already impressed in the last game against RCB, returning with figures of 4-0-20-3, something most bowlers will envy in this format of the game.
In addition, Yuvraj Singh, who slammed a half-century against Delhi Capitals and managing 23 against RCB, will be eager to make a mark in Mohali, which happens to be his 'home ground'.